3y^2-20j=-12

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Solution for 3y^2-20j=-12 equation:


Simplifying
3y2 + -20j = -12

Reorder the terms:
-20j + 3y2 = -12

Solving
-20j + 3y2 = -12

Solving for variable 'j'.

Move all terms containing j to the left, all other terms to the right.

Add '-3y2' to each side of the equation.
-20j + 3y2 + -3y2 = -12 + -3y2

Combine like terms: 3y2 + -3y2 = 0
-20j + 0 = -12 + -3y2
-20j = -12 + -3y2

Divide each side by '-20'.
j = 0.6 + 0.15y2

Simplifying
j = 0.6 + 0.15y2

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